Question

$S{F}_4$ can be hydrolyzed more easily than $S{F}_6$ because:

• A. in $S{F}_4$ due to low stability the water molecules attack on central atom.
• B. the $S$ atom in $S{F}_4$ is not sterically protected as it is surrounded by only four $F$ atoms, so the attack of water molecules can take place easily.
• C. $S$ atom in $S{F}_6$ is protected by six $F$ atoms. Thus attack by water molecules can not take place easily.
• D. All of the above options are correct.

Answer 1

Answer: (D)

All of the above options are correct.

In $S{F}_4$ hybridisation of sulphur is $ds{p}^3$. It has a dipole moment due to lone pair of electrons. Due to the presence of dipole moment, the molecule when reacted with water gets hydrolyzed.

In $S{F}_6$ the central atom sulphur hybridisation is $d^{2}S{P}^3$. dipole moment is Zero. So $S{F}_6$ does not reacts with water and does not hydrolyzed.

So the answer is true.