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Shaurya and A...

Question

Shaurya and Arjit take a straight route to the same terminal point and travel with constant speeds. At the initial moment, the positions of the two and the terminal point form an equilateral triangle. When Arjit covered a distance of 80 km, the triangle becomes right-angled. When Arjit was at a distance of 120 km from the terminal point, the Shaurya arrived at the point. Find the distance between them at the initial moment assuming that there are integral distances throughout the movements described.

300 km

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240 km

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200 km

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225 km

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Solution

The correct option is B 240 km
If the side of the initial equilateral triangle is S, then when Arjit covers (S - 120) km, Shaurya covers S km. Also, when Arjit covers a distance of 80 km, Shaurya covers a distance such that the resulting triangle is right-angled.

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The correct option is B 240 kmIf the side of the initial equilateral triangle is S, then when Arjit covers (S - 120) km, Shaurya covers S km. Also, when Arjit covers a distance of 80 km, Shaurya covers a distance such that the resulting triangle is right-angled.

The correct option is B 240 km
If the side of the initial equilateral triangle is S, then when Arjit covers (S - 120) km, Shaurya covers S km. Also, when Arjit covers a distance of 80 km, Shaurya covers a distance such that the resulting triangle is right-angled.