wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Shikha and Riya are friends and their ages differ by 2 years. Shikha's father Rajiv is twice as old as Shikha and Riya is twice as old as her sister Maya. The age of Rajiv and Maya differ by 40 years Then the age of Shikha and Riya respectively are _______

A
26 years, 24 years
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2713 years, 2913 years
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
27 years, 29 years
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Both (A) and (B)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Both (A) and (B)

First case

let the age of Shikha=x years
then Riya age=x+2 years
According to the question,
Shikha's father Rajiv age=2x
Maya age=x+22
Then 2x(x+22)=40
4xx2=80
3x=82
x=2713
Hence Shikha age is 2713years and Riya age is 2713+2=2913years


Second case

LIet Shikha's age be x, then Riya age=x2 years

According to the question,
Shikha's father Rajiv age=2x
Maya age=x22
Then 2x(x22)=40
4xx+2=80
3x=78

x=26

Hence Shikha age is 26years and Riya age is 262=24years.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications (Word problem)
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon