Shortest distance between lines →r=(5i+7j+3k)+λ(5i−16j+7k) and →r=(9i+13j+15k)+μ(3i+8j−5k):
A
10unit
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B
12unit
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C
14unit
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D
None of these
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Solution
The correct option is D None of these →r=→a1+λ→b1 →a=5i−7j+3k →b1=5i−16j+7k and from →r=→a2+λb2 →a2=9i+13j+15k →b2=3i+8j−5k ∴→a2−→a1=(9i+13j+15k)−(5i+7j+3k) =4i+6j+12k and →b1×→b2=∣∣
∣∣ijk5−16738−5∣∣
∣∣ =i(80−56)−j(−21−25)+k(40+48) =24i+46j+88k |→b1×→b2|=√(24)2+(−46)2+(88)2 =√11436 S.D=∣∣
∣∣(→a2−→a1).(→b1×→b2)→b1×→b2∣∣
∣∣ (4i+6j+12k).(24i+46j+88k)√11436 1428√11436.