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Question

Shortest distance between lines
r=(5i+7j+3k)+λ(5i16j+7k) and r=(9i+13j+15k)+μ(3i+8j5k):

A
10unit
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B
12unit
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C
14unit
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D
None of these
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Solution

The correct option is D None of these
r=a1+λb1
a=5i7j+3k
b1=5i16j+7k
and from r=a2+λb2
a2=9i+13j+15k
b2=3i+8j5k
a2a1=(9i+13j+15k)(5i+7j+3k)
=4i+6j+12k
and b1×b2=∣ ∣ijk5167385∣ ∣
=i(8056)j(2125)+k(40+48)
=24i+46j+88k
|b1×b2|=(24)2+(46)2+(88)2
=11436
S.D=∣ ∣(a2a1).(b1×b2)b1×b2∣ ∣
(4i+6j+12k).(24i+46j+88k)11436
142811436.

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