Question

Show analytically that an object placed between the pole and focus of a concave mirror produces a virtual and enlarged image. [2 MARKS]

Answer 1

Explanation: 2 Marks

$\frac{1}{v}$ = $\frac{1}{f}$ - $\frac{1}{u}$ , f < 0 (concave mirror),

f < u < 0, implies $\frac{1}{f}$ - $\frac{1}{u}$ > 0

i.e. $\frac{1}{v}$ > 0 or v > 0 (image on right; virtual)

Also $\frac{1}{v}$ < $\frac{1}{|u|}$ i.e. v > |u| (image enlarged)

Diagrammatically,