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Byju's Answer
Standard VIII
Mathematics
Divisibility by 10
Show that 24 ...
Question
Show that
2
4
n
+
4
-
15
n
-
16
, where n ∈
ℕ
is divisible by 225.
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Solution
We have,
2
4
n
+
4
-
15
n
-
16
=
2
4
n
+
1
-
15
n
-
16
=
16
n
+
1
-
15
n
-
16
=
1
+
15
n
+
1
-
15
n
-
16
=
n
+
1
C
0
15
0
+
n
+
1
C
1
15
1
+
n
+
1
C
2
15
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
+
1
-
15
n
-
16
=
1
+
(
n
+
1
)
15
+
n
+
1
C
2
15
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
+
1
-
15
n
-
16
=
1
+
15
n
+
15
+
n
+
1
C
2
15
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
+
1
-
15
n
-
16
=
n
+
1
C
2
15
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
+
1
=
15
2
n
+
1
C
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
-
1
=
225
n
+
1
C
2
+
.
.
.
+
n
+
1
C
n
+
1
15
n
-
1
Thus,
2
4
n
+
4
-
15
n
-
16
, where n ∈
ℕ
is divisible by 225.
Suggest Corrections
2
Similar questions
Q.
Show that
2
4
n
+
4
−
15
n
−
16
, where
n
∈
N
is divisible by 225.
Q.
Show that
2
4
n
+
4
−
15
n
−
16
is divisible by 225
Q.
If
2
4
n
+
4
−
15
n
−
16
,
n
∈
N
is divided by
225
, then the remainder is
Q.
If
2
4
n
+
4
−
15
n
−
16
,
n
∈
N
is divided by
225
, then the remainder is
Q.
Solve for n:
2
(
4
n
−
1
)
−
1
(
5
n
−
1
)
=
n
+
4
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