Show that : sin 90 $°$ = 2cos 45 $°$ sin 45 $°$

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Solution

$To show : \sin 90 ° = 2 \cos 45 ° . \sin 45 ° LHS : \sin 90 ° = 1 RHS = 2 \cos 45 ° . \sin 45 ° = 2 \times \frac{1}{\sqrt{2}} \times \frac{1}{\sqrt{2}} = \frac{2}{2} = 1 = LHS Hence, proved .$

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