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Question

Show that the angles subtended by an arc at the centre is double the angle subtended by same arc at any point in the remaining part of the circle
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  2. undefined
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Solution


Let AB be a chord and angle AOB be the angle subtended by it at centre and angle APB be the angle subtended at any point P on the remaining part of circle.
Now join PO and extend it to some point Q.
angle APQ is external angle to triangle POA. angle APQ = angle OPA + angle OAP.
Since OP and OA are radii of circle and hence equal, the triangle OAP is isoceles triangle. Therefore angle OPA = angle OAP.
angle APQ = 2 × angle OPA...(I)
Similarly considering triangle OPB, angle BPQ = 2 × angle OPB...(ii)
Adding (i) and (ii),
angle APQ + angle BPQ = 2 × (angle OPA + angle OPB)
angle AOB = 2 × angle APB. Proved


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