Show that the angles subtended by an arc at the centre is double the angle subtended by same arc at any point in the remaining part of the circle
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Solution
Let AB be a chord and angle AOB be the angle subtended by it at centre and angle APB be the angle subtended at any point P on the remaining part of circle. Now join PO and extend it to some point Q. angle APQ is external angle to triangle POA. → angle APQ = angle OPA + angle OAP. Since OP and OA are radii of circle and hence equal, the triangle OAP is isoceles triangle. Therefore angle OPA = angle OAP. → angle APQ = 2 × angle OPA...(I) Similarly considering triangle OPB, angle BPQ = 2 × angle OPB...(ii) Adding (i) and (ii), angle APQ + angle BPQ = 2 × (angle OPA + angle OPB) angle AOB = 2 × angle APB. Proved