Question

Show that the points $A(2,3),B(4,0)$ and $C(6,-3)$ are collinear.

Answer 1

Area of the $△ABC$ is
$=\frac{1}{2}\left[\right(0-12+18)-(12+0-6\left)\right]$
$=\frac{1}{2}(6-6)=0$
$\therefore$ The given points are collinear.