Show that the vectors a -3 i -2 j - k - b - i -3 j -5 k - c -2 i - j -4 k - form a right-angled triangle-

Let #160;ABC #160;be #160;the #160;given #160;triangle #160;and #160;AC #8594;=b #8594;=i^ 3j^+5k^CB #8594;=a #8594;=3i^ 2j^+k^AB #8594; ...

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Bisector of Angle between Two Vectors

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Show that the vectors $\vec{a} = 3 \hat{i} - 2 \hat{j} + \hat{k}, \vec{b} = \hat{i} - 3 \hat{j} + 5 \hat{k}, \vec{c} = 2 \hat{i} + \hat{j} - 4 \hat{k}$ form a right-angled triangle.

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2 \to i - \to j + \to k, \to i - 3 \to j - 5 \to k, - 3 \to i + 4 \to j + 4 \to k

A (2 \hat{i} - \hat{j} + \hat{k}), B (\hat{i} - 3 \hat{j} - 5 \hat{k}), C (3 \hat{i} - 4 \hat{j} - 4 \hat{k})

2 \hat{i} - \hat{j} + \hat{k}, \hat{i} - 3 \hat{j} - 5 \hat{k} and 3 \hat{i} - 4 \hat{j} - 4 \hat{k}

\hat{i} + \hat{j} + \hat{k}, 2 \hat{i} + 3 \hat{j} - \hat{k} and - \hat{i} - 2 \hat{j} + 2 \hat{k}

2 ˆ i - ˆ j + ˆ k, ˆ i - 3 ˆ j - 5 ˆ k

3 ˆ i - 4 ˆ j - 4 ˆ k

\vec{a} = \hat{i} + 2 \hat{j} - \hat{k}, \vec{b} = 3 \hat{i} + 2 \hat{j} + 7 \hat{k}, \vec{c} = 5 \hat{i} + 6 \hat{j} + 5 \hat{k}

\vec{a} = - 4 \hat{i} - 6 \hat{j} - 2 \hat{k}, \vec{b} = - \hat{i} + 4 \hat{j} + 3 \hat{k}, \vec{c} = - 8 \hat{i} - \hat{j} + 3 \hat{k}

\hat{a} = \hat{i} - 2 \hat{j} + 3 \hat{k}, \hat{b} = - 2 \hat{i} + 3 \hat{j} - 4 \hat{k}, \hat{c} = \hat{i} - 3 \hat{j} + 5 \hat{k}

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