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Question

Show that |1|3|5....|2n1–––––>(|n)n.

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Solution

|r|2nr–––––|n>|n

|1|2n1––––––|n>|n

|2|2n2––––––|n>|n

|3|2n3––––––|n>|n
.
.
.
|2n1––––––|1|n>|n

Multiplying the above equation we get .

(|1|2|3...|2n1––––––)2|nn>|nn

(|1|2|3...|2n1––––––)2>|n2n


(|1|2|3...|2n1––––––)>|nn


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