Question

Show that $x=2,y=1$ and $x=4,y=4$ are solutions of the system of equations.
$3x-2y=4$
$6x-4y=8$

Answer 1

The given system of equations is
$3x-2y=4$ ..(i)
$6x-4y=8$ .(ii)

Putting $x=2$ and $y=1$ in equation (i) and (ii) respectively, we get
LHS $=3\times 2-2\times 1=4=$RHS
LHS$=6\times 2-4\times 1=8=$RHS
So, $x=2,y=1$ is a solution of the given system of equations.

Similarly, Putting $x=4$ and $y=4$ in above equations

LHS $=3\times 4-2\times 4=4=$RHS
LHS$=6\times 4-4\times 4=8=$RHS

So, $x=4,y=4$ is also a solution of the given system.

Hence $x=2$, $y=1$ and $x=4,y=4$ are solutions of the given system of equations.