Question

Show the formation of sodium ion.(atomic number of sodium($\mathrm{Na}$) is 11)

Answer 1

Definition of valency.

The number of valence electrons lost or gained by an atom in order to attain stability is called valency.

The atomic number of sodium = 11

Electronic configuration = 2,8,1

since sodium has one electron in its outermost shell, it does not have stable electronic configuration.

sodium loses its one electron and achieve the stable configuration as 2,8.

$$\begin{gathered} \mathrm{Na}-1{\mathrm{e}}^{-}\to {\mathrm{Na}}^{+} \\ 2,8,12,8 \end{gathered}$$

A sodium atom($\mathrm{Na}$) has 11 protons and 11 electrons. On losing one electron, it becomes a sodium ion(${\mathrm{Na}}^{+}$).