The atomic number of sodium is 11. Then the number of electrons in sodium ion is _________ .

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Solution

The correct option is D 10
The atomic number of sodium is 11. It has 11 electrons. It loses one electron to form sodium ion.
$N a \to N a^{+} + e^{-}$
Then the number of electrons in sodium ion is $11 - 1 = 10$ .

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Similar questions

(a) The atomic number of sodium is 11. What is the number of electrons in $N a^{+}$ ?
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Show diagrammatically the electron distributions in a sodium atom and a sodium ion and also give their atomic number.

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The atomic number of sodium is 11. Then the number of electrons in sodium ion is _________ .

The correct option is D 10The atomic number of sodium is 11. It has 11 electrons. It loses one electron to form sodium ion.Na→Na++e−Then the number of electrons in sodium ion is 11−1=10.

The correct option is D 10
The atomic number of sodium is 11. It has 11 electrons. It loses one electron to form sodium ion.
$N a \to N a^{+} + e^{-}$
Then the number of electrons in sodium ion is $11 - 1 = 10$ .