Shown in the figure is a distribution of charges. The flux of electric field due to these charges through the surface is

\frac{3 q}{ϵ_{0}}

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\frac{2 q}{ϵ_{0}}

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\frac{q}{ϵ_{0}}

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Zero

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Solution

The correct option is D Zero
By Gauss law,
$ϕ = \int \to E . \to d s = \frac{q_{enclosed}}{ϵ_{0}}$
Here, $q_{e n c l o s e d} = 0$
$∴ flux = ϕ = 0$

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Shown in the figure is a distribution of charges. The flux of electric field due to these charges through the surface is

The correct option is D ZeroBy Gauss law, ϕ=∫→E.→ds=qenclosedϵ0 Here, qenclosed=0 ∴flux=ϕ=0

The correct option is D Zero
By Gauss law,
$ϕ = \int \to E . \to d s = \frac{q_{enclosed}}{ϵ_{0}}$
Here, $q_{e n c l o s e d} = 0$
$∴ flux = ϕ = 0$