Question

Shrikant from a certain place went $2km$ to East. He turned left and went $1km$. Then he turned right and went $2km$. Again he turned right and walked a distance of $9km$. Then at what distance is he from his original position?

• A. $4km$
• B. $10km$
• C. $9km$
• D. $6km$

Answer 1

Answer: (B)

$10km$

As per the given data, the following image will be formed.

Srikant starts from point $A$ and stops at $B$.

Now, Srikant form a right angled triangle $BCD$ right angled at $C$.

$BC=8km,CD=2km,AD=2km$

By Pythagoras theorem, $B{D}^2=B{C}^2+D{C}^2=8^2+2^2=68$.

$BD=8km$

Thus, Srikant is $8+2=10km$ far from starting point.