Question

SI units of $a$ is :

• A. $M^3$
• B. $m^{-1}s$
• C. $m^2{s}^{-2}$
• D. $m{s}^2$

Answer 1

The correct option is B $m^{-1}s$

$a=\sqrt{\frac{M_0}{2\pi RT}}$
$M_0:kgmo{l}^{-1};R:\frac{kg{m}^2{s}^{-2}}{molK};T:K$
$a=\sqrt{\frac{kgmo{l}^{-1}}{\frac{kg{m}^2{s}^{-2}}{molK}\times K}}=m^{-1}s$
Hence, SI units of $a$ is $m^{-1}s$.