Side of an equilateral triangle is $4 c m$ . Its area is:

4 \sqrt{3} c m^{2}

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\frac{\sqrt{3}}{4} c m^{2}

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\sqrt{3} c m^{2}

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2 \sqrt{3} c m^{2}

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Solution

The correct option is C $4 \sqrt{3} c m^{2}$
Area of equilateral triangle $= \frac{\sqrt{3}}{4} (s i d e)^{2}$
$= \frac{\sqrt{3}}{4} \times 4 \times 4 = 4 \sqrt{3} c m^{2}$

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