Question

The area of an equilateral triangle is 4 $\sqrt{3}c{m}^2$. Its perimeter is

(a) 9 cm (b) 12 cm (c) 12$\sqrt{3}$ cm (d) 6$\sqrt{3}$ cm

Answer 1

The area of an equilateral triangle of side a = $\frac{\sqrt{3}{a}^2}{4}$

$4\sqrt{3}=\frac{\sqrt{3}{a}^2}{4}$

$a^2=16$

a = 4 cm.

Hence the side of the equilateral triangle = 4 cm.

Perimeter = $3a=3\times 4=12$