Question

The perimeter of an equilateral triangle of area $64\sqrt{{3cm}^2}$ is

• A. $192\sqrt{3cm}$
• B. 64 cm
• C. 16 cm
• D. 48 cm

Answer 1

The correct option is D 48 cm

$Areaofequationtriangle=\frac{\sqrt{3}}{4}{a}^{2}64\sqrt{3}=\frac{\sqrt{3}}{4}{a}^{2}or{a}^2=64\times 4ora=8\times 2=16Perimeter=3a=3\times 16=48cm$'