Silver nitrate precipitates the entire chlorine as silver chloride from a solution of the complex salt PtCl4- 6NH3 and only one-fourth of the chlorine from a solution of the salt PtCl4- 3NH3- Determine the coordination number of the platinum in each case- The sum of the coordination no- in the two cases is equal to 12- If true- enter 1 else enter 0-

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Byju's Answer

Standard XII

Chemistry

Linkage Isomerism

Silver nitrat...

Question

Silver nitrate precipitates the entire chlorine as silver chloride from a solution of the complex salt $P t C l_{4} \cdot 6 N H_{3}$ and only one-fourth of the chlorine from a solution of the salt $P t C l_{4} \cdot 3 N H_{3}$ . Determine the coordination number of the platinum in each case. The sum of the coordination no. in the two cases is equal to 12. If true, enter 1 else enter 0.

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Solution

Silver nitrate precipitates the entire chlorine as silver chloride from a solution of the complex salt $P t C l_{4} \cdot 6 N H_{3}$ .
Thus, all the 4 Cl atoms are present in the ionization sphere. Hence, the complex can be written as $[P t (N H_{3})_{6}] C l_{4}$ .
Silver nitrate precipitates only one-fourth of the chlorine from a solution of the salt $P t C l_{4} \cdot 3 N H_{3}$ .
Hence, only one Cl atom is present in the ionization sphere and 3 Cl atoms are present in the coordination sphere.
Hence, the complex can be written as $[P t (N H_{3})_{3} C l_{3}] C l$ .
Thus, the coordination number of the platinum in each case is 6.
The sum of the coordination no. in the two cases is equal to $6 + 6 = 12$ .

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