- p - q is equal toA- P - qB- p - qC - - p - qD- P - q

The correct option is B p ∨ (∼ q)∼ ((∼ p)∧ q) ≡∼ (∼ p)∨∼ q ≡ p ∨ (∼ q) ...

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Negation

∼∼ p ∧ q is e...

Question

$\sim ((\sim p) \land q)$ is equal to

p \lor (\sim q)

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p \lor q

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p \land (\sim q)

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\sim p \land \sim q

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Solution

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\sim (\sim p)) \land q

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$\sim (\sim p \land q)$ is logically equivalent to

(p \land \sim q) \lor q \lor (\sim p \land q)

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