Simplify :
$10 a^{2} - 15 b^{2} + 20 c^{2}$

5 (2 a^{2} - 3 b^{2} + 4 c^{2})

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5 (2 a - 3 b^{2} + 4 c^{2})

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5 (10 a^{2} - 3 b^{2} + 4 c^{2})

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5 (2 a^{2} + 3 b^{2} + 4 c^{2})

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Solution

The correct option is A $5 (2 a^{2} - 3 b^{2} + 4 c^{2})$
$10 a^{2} - 15 b^{2} + 20 c^{2}$
The common factor $= 5$
Thus, $10 a^{2} - 15 b^{2} + 20 c^{2}$
$= 5 (2 a^{2} - 3 b^{2} + 4 c^{2})$

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Similar questions

2 a^{2} - 3 b^{2} + 4 c^{2} - 5 d^{2}

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(4a+3b)² -(4a-3b)²+48ab

{(4 a + 3 b)}^{2} - {(4 a - 3 b)}^{2} + 48 a b

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