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Byju's Answer
Standard VII
Mathematics
Exponents with Like Bases
Simplify: 22...
Question
Simplify:
2
2
×
3
3
×
2
4
×
3
5
×
3
6
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Solution
Given that:
2
2
×
3
3
×
2
4
×
3
5
×
3
6
=
2
(
2
+
4
)
×
3
(
3
+
5
+
6
)
Using [
a
m
1
×
.
.
.
×
a
m
n
=
a
m
1
+
.
.
.
.
.
.
.
m
n
]
=
2
6
×
3
14
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0
Similar questions
Q.
Simplify:
(
3
3
)
−
2
×
(
2
2
)
−
3
(
2
4
)
−
2
×
3
−
4
×
4
−
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Q.
Simplify:
3
5
×
2
2
×
7
−
3
7
−
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×
3
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Q.
The marks obtained by
19
students of a class are
27
,
36
,
22
,
31
,
25
,
26
,
33
,
24
,
37
,
32
,
29
,
28
,
36
,
35
,
27
,
26
,
32
,
35
and
28
. Find the upper quartile.
Q.
The marks obtained by
19
students of a class are
27
,
36
,
22
,
31
,
25
,
26
,
33
,
24
,
37
,
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,
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,
35
,
27
,
26
,
32
,
35
and
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. Find the inter quartile.
Q.
Find the median of:
26
,
33
,
41
,
18
,
30
,
22
,
36
,
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and
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