Question

Simplify $(2+8i)(1-4i)-(3-2i)(6+4i)$

(Note$:i=\sqrt{-1}$)

• A. $8$
• B. $26$
• C. $34$
• D. $50$

Answer 1

The correct option is A $8$

The value of $(2+8i)(1-4i)-(3-2i)(6+4i)$

$=$ $(2+8i-8i-32i^2)-(18-12i+12i-8i^2)$

$=$ $2-32i^2-18+8i^2$

Put the given value of $i=\sqrt{-1}$, we get

$=$ $2-32(\sqrt{-1}{)}^2-18+8(\sqrt{-1}{)}^2$

$=$ $2-32(-1)-18+8(-1)$

$=$ $2+32-18-8$

$=$ $34-26=8$