Question

Simplify:
$2a-[4b-\{4a-(3b-2a+2b)\left\}\right]$

Answer 1

$\mathrm{2a-[4b-\{4a-(3b-}\overline{\mathrm{2a+2b}})\}]$
We will first remove the innermost grouping symbol bar bracket. Next, we will remove ( ), followed by { } and then [ ].

∴ $\mathrm{2a-[4b-\{4a-(3b-}\overline{\mathrm{2a+2b}})\}]$
= 2a-[4b-{4a-(3b-2a-2b)}]
= 2a-[4b-{4a-(b-2a)}]
= 2a-[4b-{4a-b+2a}]
=2a-[4b-{6a-b}]
= 2a-[4b-6a+b]
= 2a-[5b-6a]
= 2a-5b+6a
= 8a-5b