Simplify: $(3 x + 2)^{2} = 3 x^{2} + 6 x + 4$

(3 x - 2)^{2} = 9 x^{2} - 12 x + 4

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(x + 2)^{2} = x^{2} + 4 x + 4

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(3 x + 2)^{2} = 9 x^{2} + 12 x + 4

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(x - 2)^{2} = x^{2} - 4 x + 4

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Solution

The correct option is C $(3 x + 2)^{2} = 9 x^{2} + 12 x + 4$
LHS $= (3 x + 2)^{2} = (3 x)^{2} + 2 \times 3 x \times 2 + 2^{2}$
$= 9 x^{2} + 12 x + 4$
Thus, $(3 x + 2)^{2} \neq 3 x^{2} + 6 x + 4$ ,but $(3 x + 2)^{2}$
$= 9 x^{2} + 12 x + 4$ is the correct statement.

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