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Question

Simplify :4 23÷( 3-13 ) +( 25of 56)


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Solution

Step 1 : Convert the mixed fractions into improper fractions

423 =(4×3)+23 =12+23 =143

Step 2 : Simplifying the first bracket

( 3-13 ) ,3 we can write it as 31

3-13 = 31 -13

Step 3: The bottom numbers are different, To make it same take the L.C.M of 1 and 3

L.C.M of 1and 3 is 3

Step 4: Convert both the fraction into equivalent like fractions with their L.C.M as common denominator

31=3×31×3 =93

13=1×13×1 =13

Step 5: Subtract the numerators and put the answer over the denominator

93-13 =9-13 =83

Step 6 : Simplifying the second bracket

( 25of 56)

Replace the word ‘ of ’ with the multiplication sign ‘ x ’ and do multiplication

25×56 = 2×55×6=1030

4 23÷( 3-13 ) +( 25of 56) = 143÷83+1030

Step 7 : First do division

143÷83

Write the reciprocal of the second fraction ( that one you want to divide by ) with the sign of multiplication (×) and do multiplication

143×38=14×33×8=4224

143÷83+1030 =4224+1030

Step 8: The bottom numbers are different, To make it same take the L.C.M of 24 and 30

L.C.M of 24and 30 is 120

Step 9: Convert both the fraction into equivalent like fractions with their L.C.M as common denominator

4224=42×524×5 =210120

1030=10×430×4 =40120

Step 10: Add the numerators and put the answer over the denominator

210120+40120 =250120

Step11: Simplify the fraction

Divide numerator 250 by the denominator 120

250120=210120

Here ,10120=10÷10120÷10=112

210120 =2112

Hence, 4 23÷( 3-13 ) +( 25of 56) =2112


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