Simplify and express in exponential form:
$4^{3}$ x $4^{- 2}$ x $16^{2}$

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Solution

$a^{x}$ $\times$ $a^{y}$ = $a^{x + y}$

∴ $4^{3} \times 4^{- 2} \times 16^{2} = 4^{3} \times 4^{- 2} \times {((4)^{2})}^{2} = 4^{3} \times 4^{- 2} \times 4^{4} = 4^{3 - 2 + 4} = 4^{5}$

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