Simplify and give reasons:
$4^{- 3}$

\frac{1}{64}

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\frac{1}{4}

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\frac{1}{24}

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None of these

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Solution

The correct option is A $\frac{1}{64}$

we know that

$∵ a^{- m} = \frac{1}{a^{m}}$

$∴ 4^{- 3} = \frac{1}{4^{3}}$

$= \frac{1}{64}$

Suggest Corrections

Similar questions

{(\frac{1}{2})}^{- 3} \times {(\frac{1}{4})}^{- 3} \times {(\frac{1}{5})}^{- 3}

(4^{0} + 5^{- 1}) \times 5^{2} \times \frac{1}{3}

(64)^{- \frac{2}{3}} \times {(\frac{1}{4})}^{- 3}

In ch .1

A question

to simplify

64^1/3(64^1/3 - 64^2/3)

in this the solution is given as

= (4^3)^ -1/3[ ( 4^3)^1/3 - (4^3)^2/3 ]

how -1/3 came ?

{[(64)^{- 3} \times (81)^{- \frac{9}{4}}]}^{- \frac{1}{9}}

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