Simplify and write the expression in exponential form: $4^{3}$ x $4^{- 2}$ x $16^{2}$

$4^{3}$

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$4^{4}$

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$4^{5}$

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$4^{6}$

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Solution

The correct option is C
$4^{5}$

We know that $a^{x}$ $\times$ $a^{y}$ = $a^{x + y}$ .

$4^{3} \times 4^{- 2} \times 16^{2} = 4^{3} \times 4^{- 2} \times {((4)^{2})}^{2} = 4^{3} \times 4^{- 2} \times 4^{4} = 4^{3 - 2 + 4} = 4^{5}$

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4^{3}

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