Question

Simplify and write the following in exponential form : $2^0\times {\left(3^2\right)}^4-{\left(4^2\right)}^0+{\left(5^2\right)}^3$ .

Answer 1

Given that , $2^0\times {\left(3^2\right)}^4-{\left(4^2\right)}^0+{\left(5^2\right)}^3$

$=1\times {\left(3\right)}^{2\times 4}-{\left(4\right)}^{2\times 0}+{\left(5\right)}^{2\times 3}$

$=1\times 3^8-{\left(4\right)}^0+5^6$

$=3^8-1+5^6$

$=22185$

Hence , the required value is $3^8-1+5^{6}or22185$.