The correct option is A b^2 14b + 49 (b nbsp; 7)^2 Using (a b)^2=a^2 2ab+b^2 we get, b^2 2(b)(7)+7^2 =b^2 14b+49 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation Using Algebraic Identities

Simplify b-...

Question

Simplify $(b - 7)^{2}$

b^{2} - 14 b + 49

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

b^{2} - 16 b + 49

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b^{2} - 10 b + 49

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b^{2} - 12 b + 49

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $b^{2} - 14 b + 49$
$(b - 7)^{2}$
Using $(a - b)^{2} = a^{2} - 2 a b + b^{2}$ we get,
$b^{2} - 2 (b) (7) + 7^{2}$
$= b^{2} - 14 b + 49$

Suggest Corrections

Similar questions

(b - 7)^{2}

\frac{8}{27} a^{7} b^{2} + \frac{4}{9} a^{5} b^{2}

25 a^{2} + b^{2} - 100 a b - 49

a^{2} - 2 a b + b^{2} = (a - b)^{2}

y^{2} - 14 y + 49

(A + B)^{2}

x \geq 4, A^{2} = x^{2} + 12 x + 36

B^{2} = 4 x^{2} - 28 x + 49

Join BYJU'S Learning Program