Simplify:
${cos}^{2} x + {sin}^{2} x + {tan}^{2} x$

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Solution

Solution :-
$c o s^{2} x + s i n^{2} x + t a n^{2} x$

$= 1 + t a n^{2} x$

$= {sec}^{2} x$

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Similar questions

Prove that

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(ii) $\frac{1 - cos2x}{1 + cos 2 x} = {tan}^{2} x$

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sin 2 x + cos 2 x

\frac{1}{5}

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\frac{1 + sin x + cos x + sin 2 x + cos 2 x}{tan 2 x} = 0

\frac{α^{2}}{1 - {tan}^{2} x} = \frac{{sin}^{2} x + α^{2} - 2}{cos 2 x}

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