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Byju's Answer
Standard X
Mathematics
Quadratic Polynomial
Simplify : ...
Question
Simplify :
1
x
2
−
5
x
+
6
−
1
x
2
−
3
x
+
2
A
2
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
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B
(
x
−
4
)
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
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C
2
(
x
−
2
)
(
x
−
1
)
(
x
−
2
)
(
x
−
4
)
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D
(
x
−
3
)
(
x
−
4
)
(
x
−
2
)
(
x
−
3
)
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Solution
The correct option is
A
2
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
1
x
2
−
5
x
+
6
−
1
x
2
−
3
x
+
6
⇒
x
2
−
3
x
+
2
−
(
x
2
−
5
x
+
6
)
(
x
2
−
5
x
+
6
)
(
x
2
−
3
x
+
2
)
⇒
2
x
−
4
(
x
2
−
2
x
−
x
+
2
)
(
x
2
−
3
x
−
2
x
+
6
)
⇒
2
(
x
−
2
)
(
x
(
x
−
2
)
−
(
x
−
2
)
)
(
x
(
x
−
3
)
−
2
(
x
−
3
)
)
⇒
2
(
x
−
2
)
(
x
−
2
)
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
⇒
2
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
Suggest Corrections
0
Similar questions
Q.
If
x
2
+
5
x
+
1
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
=
A
x
+
1
+
B
(
x
+
1
)
(
x
+
2
)
+
C
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
, then C=
Q.
Which of the following are quadratic equations?
(i) x
2
+ 6x − 4 = 0
(ii)
3
x
2
-
2
x
+
1
2
=
0
(iii)
x
2
+
1
x
2
=
5
(iv)
x
-
3
x
=
x
2
(v)
2
x
2
-
3
x
+
9
=
0
(vi)
x
2
-
2
x
-
x
-
5
=
0
(vii) 3x
2
− 5x + 9 = x
2
− 7x + 3
(viii)
x
+
1
x
=
1
(ix) x
2
− 3x = 0
(x)
x
+
1
x
2
=
3
x
+
1
x
+
4
(xi) (2x + 1) (3x + 2) = 6(x − 1) (x − 2)
(xii)
x
+
1
x
=
x
2
,
x
≠
0
(xiii) 16x
2
− 3 = (2x + 5) (5x − 3)
(xiv) (x + 2)
3
= x
3
− 4
(xv) x(x + 1) + 8 = (x + 2) (x − 2)