Question

Simplify $\frac{16\times 2^{n+1}-4\times 2^n}{16\times 2^{n+2}-2\times 2^{n+2}}$

Answer 1

$\frac{16\times 2^{n+1}-4\times 2^n}{16\times 2^{n+2}-2\times 2^{n+2}}$
$\frac{16\times 2^n\times 2^1-4\times 2^n}{16\times 2^n\times 2^2-2\times 2^n\times 2^2}$
$\frac{2^n(32-4)}{2^n(16\times 4-2\times 4)}=\frac{2^n(32-4)}{2^n(64-8)}$
$=\frac{28}{56}=\frac{1}{2}$