The correct option is B x^2x^2 + y^2 The value of xyxy+yx is ⇒xy(xy+yx) ⇒xy ( x^2+y^2xy ) ⇒x^2x^2+y^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Higher Order Derivatives

Simplify xy...

Question

Simplify $\frac{\frac{x}{y}}{\frac{x}{y} + \frac{y}{x}}$

\frac{1}{x y}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{x^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{y^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{x^{2}}{x^{2} + y^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{x y}{x y + y^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{x^{2}}{x^{2} + y^{2}}$
The value of $\frac{\frac{x}{y}}{\frac{x}{y} + \frac{y}{x}}$ is
$\Rightarrow \frac{x}{y (\frac{x}{y} + \frac{y}{x})}$
$\Rightarrow \frac{x}{y (\frac{x^{2} + y^{2}}{x y})}$
$\Rightarrow \frac{x^{2}}{x^{2} + y^{2}}$

Suggest Corrections

Similar questions

x^{2} + y^{2} - x y = 3

y - x = 1

\frac{x y}{x^{2} + y^{2}}

\frac{x^{2} - x y}{y^{2} - x y}

\frac{x}{y}

x^{2} + y^{2} - x y = 3 and y - x = 1, then \frac{x y}{x^{2} + y^{2}} =___________.

x^{2} + y^{2} + z^{2} - x y - y z - z x = \frac{1}{2} [(x - y)^{2} + (y - z)^{2} + (z - x)^{2}]

x^{2} y^{2} + x y + 1

x = 3

y = 2

Join BYJU'S Learning Program