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Question

Simplify :
dydx=a2x2a2+x2

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Solution

dydx=a2x2a2+x2=2x(a2+x2)2x(a2x2)(a2+x2)22a2x2a2+x2=2x(2a2)(a2+x2)2×a2+x22a2x2=2a2x(a2+x2)3/2(a2x2)1/2

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