wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify :
dydx=a2x2a2+x2

Open in App
Solution

dydx=a2x2a2+x2=2x(a2+x2)2x(a2x2)(a2+x2)22a2x2a2+x2=2x(2a2)(a2+x2)2×a2+x22a2x2=2a2x(a2+x2)3/2(a2x2)1/2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon