Question

Simplify:
$\frac{{\left(2^5\right)}^2\times 7^3}{8^3\times 7}$

Answer 1

We have,

$\frac{(2^5{)}^2\times 7^3}{8^3\times 7}$

$=\frac{2^{10}\times 7^2}{(2^3{)}^3}$

$=\frac{2^{10}\times 7^2}{2^9}$

$=2\times 7^2$

$=98$

Hence, this is the answer.