√(3)4+16√(3) =√(3)4+16√(3)×√(3)√(3) =√(3)4+√(3)18 =9√(3)+2√(3)36 since L.C.M of 4 and 18 is 36 =11√(3)36 ...

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Implicit Differentiation

Simplify: √3...

Question

Simplify: $\frac{\sqrt{3}}{4} + \frac{1}{6 \sqrt{3}}$

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Solution

$\frac{\sqrt{3}}{4} + \frac{1}{6 \sqrt{3}}$
$= \frac{\sqrt{3}}{4} + \frac{1}{6 \sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}$
$= \frac{\sqrt{3}}{4} + \frac{\sqrt{3}}{18}$
$= \frac{9 \sqrt{3} + 2 \sqrt{3}}{36}$ since L.C.M of $4$ and $18$ is $36$
$= \frac{11 \sqrt{3}}{36}$

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