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Question

Simplify: 12ab36a2b3ab (given that ab0)

A
6b2a
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B
2b23a
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C
4b22a
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D
3b22a
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Solution

The correct option is C 4b22a
(2b2a) or 4b22a: First, factor out common terms in the numerator. Then, cancel terms in both the numerator and denominator:
6ab(2b2a)3ab=2(2b2a) or 4b22a

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