Question

Simplify

$\frac{x^2-xy}{x^{2}y}-\frac{y+z}{yz}-\frac{2z^2-xy}{z^{2}x}$, then the answer is $-\frac{3}{x}$
If true then enter $1$ and if false then enter $0$

Answer 1

$\frac{x^2-xy}{x^{2}y}-\frac{y+z}{yz}-\frac{2z^2-xy}{z^{2}x}=\frac{z^2(x^2-xy)-x^{2}z(y+z)-xy(2z^2-xy)}{z^2{x}^{2}y}=\frac{z^2{x}^2-z^{2}xy-z{x}^{2}y-z^2{x}^2-2z^{2}xy+y^2{x}^2}{z^2{x}^{2}y}=\frac{-4z^{2}xy+y^2{x}^2}{z^2{x}^{2}y}=-\frac{4}{x}+\frac{y}{z^2}$