Question

Simplify: $(16x^3{y}^2{z}^2+16x^2{y}^2{z}^3+16x^2{y}^3{z}^2)÷8xyz$

• A. $2(x^{2}yz+xy{z}^2+x{y}^{2}z-xyz)$
• B. $(x^{2}yz+xy{z}^2+x{y}^{2}z)$
• C. $2x^{2}yz+2xy{z}^2+2x{y}^{2}z$
• D. $2x^2{y}^{2}z+2x{y}^2{z}^2+2x^{2}y{z}^2-xyz$

Answer 1

The correct option is C $2x^{2}yz+2xy{z}^2+2x{y}^{2}z$

Given, $(16x^3{y}^2{z}^2+16x^2{y}^2{z}^3+16x^2{y}^3{z}^2)÷8xyz$

$=\frac{16x^3{y}^2{z}^2+16x^2{y}^2{z}^3+16x^2{y}^3{z}^2}{8xyz}$

$=\frac{8xyz(2x^{2}yz+2xy{z}^2+2x{y}^{2}z)}{8xyz}$

$=2x^{2}yz+2xy{z}^2+2x{y}^{2}z$