Question

Simplify: $\frac{b^2}{\sqrt{a^2+b^2}+a}$

Answer 1

$\frac{b^2}{\sqrt{a^2+b^2}+a}$
Multiplying numerator and denomenator by $\sqrt{a^2+b^2}-a$
$\frac{b^2\times (\sqrt{a^2+b^2}-a)}{(\sqrt{a^2+b^2}+a)(\sqrt{a^2+b^2}-a)}$
$\frac{b^2\times (\sqrt{a^2+b^2}-a)}{\text{/}{a}^2+b^2-\text{/}{a}^2}$
$\frac{\text{/}{b}^2\times \sqrt{a^2+b^2}-a}{\text{/}{b}^2}$
$\sqrt{a^2+b^2}-a$