Question

Simplify: $(\frac{x^2}{3}-\frac{4x}{7}+11)-(\frac{x}{7}-3+2x^2)-(\frac{2x}{7}-\frac{2x^2}{3}+2)$

Answer 1

We have,

$(\frac{x^2}{3}-\frac{4x}{7}+11)-(\frac{x}{7}-3+2x^2)-(\frac{2x}{7}-\frac{2x^2}{3}+2)$

$=\frac{x^2}{3}-\frac{4x}{7}+11-\frac{x}{7}+3-2x^2-\frac{2x}{7}+\frac{2x^2}{3}-2$

$=\frac{x^2+2x^2}{3}-\left(\frac{4x+x+2x}{7}\right)+11+3-2x^2-2$

$=\frac{3x^2}{3}-\left(\frac{7x}{7}\right)-2x^2+12$

$=x^2-x-2x^2+12$

$=-x^2-x+12$

Hence, this is the answer.