Question

Simplify :
$\sqrt[4]{481}-8\sqrt[3]{3216}+15\sqrt[3]{332}+\sqrt{225}$.

Answer 1

$\sqrt[4]{481}-8\sqrt[3]{3216}+15\sqrt[5]{532}+\sqrt{225}$

$={\left(3^4\right)}^{\frac{1}{4}}-8{\left(6^3\right)}^{\frac{1}{3}}+15{\left(2^5\right)}^{\frac{1}{5}}+15$

$=3-8\times 6+15\times 2+15$

$=3-48+30+15$

$=48-48$

$=0$