Question

Simplify:$\sqrt[4]{481}-8\sqrt[3]{3343}+15\sqrt[5]{532}+\sqrt{225}$

Answer 1

$\sqrt[4]{481}-8\sqrt[3]{3343}+15\sqrt[5]{532}+\sqrt{225}$

$={\left(81\right)}^{\frac{1}{4}}-8{\left(343\right)}^{\frac{1}{3}}+15{\left(32\right)}^{\frac{1}{5}}+15$

$={\left(3^4\right)}^{\frac{1}{4}}-8{\left(7^3\right)}^{\frac{1}{3}}+15{\left(2^5\right)}^{\frac{1}{5}}+15$

$=3-8\times 7+15\times 2+15$

$=3-56+30+15$

$=48-56$

$=-8$