The correct option is D 24x
Given expression is
(3x+2)2−(3x−2)2.
Using the identity: (a+b)2=a2+2ab+b2
and
(a−b)2=a2−2ab+b2,
the above expression can be written as,
(3x+2)2−(3x−2)2
=[(3x)2+2(3x)(2)+(2)2]−[(3x)2−2(3x)(2)+(2)2]
=[(9x2+12x+4)−(9x2−12x+4)]
=9x2−9x2+12x+12x+4−4
=24x