3
Question
Simplify the following algebraic expression by removing grouping symbols.a−[2b−{3a−(2b−3c)}]
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Solution
We have:
=a−[2b−{3a−(2b−3c)}]
=a−[2b−{3a−2b+3c}]
=a−[2b−3a+2b−3c]
=a−[−3a+4b−3c]
=a−3a−4b+3c
=−2a−4b+3c
We have:
=a−[2b−{3a−(2b−3c)}]
=a−[2b−{3a−2b+3c}]
=a−[2b−3a+2b−3c]
=a−[−3a+4b−3c]
=a−3a−4b+3c
=−2a−4b+3c
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