Question

Simplify the following :
$\frac{3-i}{2+i}+\frac{3+i}{2-i}$

Answer 1

$\frac{3-i}{2+i}$$+\frac{3+i}{2-i}$

$⟹\frac{(3-i)(2-i)+(2+i)(3+i)}{2^2+1}$

$⟹\frac{6-5i-1+6+5i-1}{5}$

$⟹\frac{10}{5}=2$